Q1. The probability of getting a bad egg in a lot of 400 is 0.035. The number of bad eggs in the lot is:
(a) 7
(b) 14
(c) 21
(d) 28

Q2. An urn contains lottery tickets numbered from 1 to 100. If a ticket is selected at random, then the probability that it is a perfect square is?
(a) 0.1
(b) 0.08
(c) 0.09
(d) 0.01

Q3. If the probability of winning a game is 0.3, the probability of losing it is?
(a) 1.3
(b) 1
(c) 0.7
(d) 0.1

Q4. The total number of events of throwing 10 coins simultaneously is
(a) 1024
(b) 512
(c) 100
(d) 10

Q5. If the probability of an event is P, the probability of its complementary event will be:
(a) P – 1
(b) P
(c) 1 – p
(d) 1 – 1/p

Q6. If P(A) denotes the probability of an event then:
(a) P(A) < 0 (b) P(A) > 0
(b) 0 = P(A) = 1
(c) -1 = P(A) = 0
(d) 1 = P(A) = 1

Q7. An event is very unlikely to happen. Its probability is closest to:
(a) 0.0001
(b) 0.001
(c) 0.01
(d) 0.1

Q8. A card is drawn from a deck of 52 cards. The event E is that card is not an ace of hearts. The number of outcomes favourable to E is:
(a) 4
(b) 13
(c) 48
(d) 51

Q9. A girl calculate that the probability of her winning the first prize in a lottery is 0.08. If 6000 tickets are sold, how many tickets has she bought?
(a) 40
(b) 240
(c) 480
(d) 750

Q10. Probability Class 10 MCQ Question 4. The total number of events of throwing 10 coins simultaneously is
(a) 1024
(b) 512
(c) 100
(d) 10

Q11. The median of first 10 prime numbers is
(a) 11
(b) 12
(c) 13
(d) none of these

Q12. The measure of central tendency which is given by the x-coordinate of the point of intersection of the ‘more than’ ogive and ‘less than’ ogive is –
(a) Mean
(b) Median
(c) Mode
(d) None of these

Q13. While computing mean of a grouped data, we assume that the frequencies are
(a) centered at the lower limits of the classes
(b) centered at the upper limits of the classes
(c) centered at the class marks of the classes
(d) evenly distributed over all the classes

Q14. The mean of the first 10 natural numbers is
(a) 5
(b) 6
(c) 4.5
(d) 5.5
Q15. Mean of 100 items is 49. It was discovered that three items which should have been 60, 70, 80 were wrongly read as 40, 20, 50 respectively. The correct mean is
(a) 48
(b) 49
(c) 50
(d) 60

Q6. The marks obtained by 9 students in Mathematics are 59, 46, 30, 23, 27, 44, 52, 40 and 29. The median of the data is
(a) 30
(b) 35
(c) 29
(d) 40

Q17. The wickets taken by a bowler in 10 cricket matches are 2, 6, 4, 5, 0, 3, 1, 3, 2, 3. The mode of the data is
(a) 1
(b) 2
(c) 3
(d) 4

Q18. The mean and the median of a distribution are 45.9 and 46 respectively. The mode will be
(a) 45
(b) 47
(c) 48
(d) 46.2

Q19. Mode is the
(a) middle most frequent value
(b) least frequent value
(c) maximum frequent value
(d) none of these

Q20. While computing mean of grouped data, we assume that the frequencies are all the classes
(a) evenly distributed over
(b) centred at the classmarks of the classes
(c) centred at the upper limits of the classes
(d) centred at the lower limits of the classes